AnswersCA-Common Core Math II A-CRModeling with Quadratic Equations

3.7 Modeling with Quadratic Equations Answers

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8

Aisha wants to make two quilts, each with the same area. The first quilt will be square with sides s feet long. The second quilt will be a rectangle with a width that is half the length of a side of the square quilt and a length that is 6 feet longer than a side length of the square quilt.

A
s2 = (s + 6)
Option A
B
s2 = (s)(s + 6)
C
s2 = (6s)
Option C
D
s2 = (s)(6s)
9

The product of two positive numbers is 1,800. One number is twice the other number. The equation to determine the two numbers, with x representing the value of the lesser number, is x(2x) = 1,800.

A
24
B
30
C
48
D
60
10

Sergei buys a rectangular rug for his living room. He measures the diagonal of the rug to be 18 feet. The length of the rug is 3 feet longer than the width.

A
10.4 feet by 7.4 feet
B
11.1 feet by 8.1 feet
C
13.4 feet by 10.4 feet
D
14.1 feet by 11.1 feet
11

The product of two consecutive integers is 342. Which quadratic equation can be used to find x, the greater number?

A
x2 + 1 = 342
B
x2 − 1 = 342
C
x2 − x + 342 = 0
D
x2 − x − 342 = 0
12

A rectangle’s length is 2 units more than twice its width. Its area is 40 square units. The equation w(2w + 2) = 40 can be used to find w, the width of the rectangle.

A
4 units
B
5 units
C
10 units
D
12 units
13

Kyla makes a triangular school pennant. The area of the triangle is 180 square inches. The base of the pennant is z inches long. The height is 6 inches longer than twice the base length.

Question illustration
A
12 inches
B
15 inches
C
30 inches
D
36 inches
14

A rectangle’s width is one-fourth of its length. Its area is 9 square units. The equation l(l) = 9 can be used to find l, the length of the rectangle.

Question illustration
A
0.75 units
B
1.5 units
C
3 units
D
6 units
15

The projectile motion of an object can be modeled usings(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s2.

A
s(t) = –4.9t2 + 39.2
B
s(t) = –4.9t2 + 39.2t
C
s(t) = –4.9t2 + 39.2t + 39.2
D
s(t) = –4.9t2 + 39.2t – 39.2

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