AnswersIntegrated Math 2A - Mr. Katykhin 26Solving Linear-Quadratic Systems

3.8 Solving Linear-Quadratic Systems Answers

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The first three steps in determining the solution set of the system of equations algebraically are shown.y = x2 − x − 3 y = −3x + 5

Question illustration
A
(−2, −1) and (4, 17)
B
(−2, 11) and (4, −7)
C
(2, −1) and (−4, 17)
D
(2, 11) and (−4, −7)
3

Which parabola will have one real solution with the line y = x – 5?

Question illustration
A
y = x2 + x – 4
B
y = x2 + 2x – 1
C
y = x2 + 6x + 9
D
y = x2 + 7x + 4
6

Which line will have no solution with the parabola y – x + 2 = x2?

Question illustration
A
y = –3x –3
B
y = –2x –3
C
y = 2x –3
D
y = 3x –3
11

Question text not available

Question illustration
A
-1
B
-3
C
0
D
3
12

Which represents the solution(s) of the graphed system of equations, y = x2 + x – 2 and y = 2x – 2?

Question illustration
A
(–2, 0) and (0, 1)
B
(0, –2) and (1, 0)
C
(–2, 0) and (1, 0)
D
(0, –2) and (0, 1)

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