The graph of an absolute value function has a vertex at (–2, 3) and passes through the point (–1, 0). Using transformations of the parent function, has the graph been dilated by a scale factor other than 1? Explain.
Yes, the graph has been dilated by a scale factor of 3. To determine this, use the standard form of an absolute value function, y = a|x – h| + k, where (h, k) is the vertex. Substituting the vertex (-2, 3) and the point (-1, 0) into the equation gives 0 = a|(-1) – (-2)| + 3. Simplifying this results in 0 = a(1) + 3, which means a = –3. Since the absolute value of a is 3 (not 1), the graph has undergone a vertical stretch (dilation).
Find the vertex of the given function. f(x) = |x – 5| + 10 The vertex is at (, ).
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Find the vertex of the given function. f(x) = |x + 1| - 7 The vertex is at (, ).
Which of the following is a horizontal stretch of the parent function?
Which graph shows f(x) = 0.5|x + 3| – 2?



Which graph shows f(x) = |x| reflected across the x-axis, translated 2 units down and 1 unit to the left?
Given the function f(x) = 4|x – 5| + 3, for what values of x is f(x) = 15?
Which of the following did you include in your answer?
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Which equation represents the reflected and translated function? f(x) = –|x – 2| – 1✔ f(x) = –|x + 1| – 2 f(x) = |x + 2| – 1
Given the function f(x) = –0.5|2x + 2| + 1, for what values of x is f(x) = 6?
What are the acceptable diameters for the golf balls?
What are the domain and range of the function?




What are the domain and range of the function?




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