Addition and Subtraction Inequalities Answers

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Emma is training for a 10-kilometer race. She wants to beat her last 10-kilometer time, which was 1 hour 10 minutes. Emma has already run for 55 minutes. Which inequality can be used to find how much longer she can run and still beat her previous time? (1 hr = 60 min)

A
70 greater-than 7 minus 55
Option A
B
70 less-than t minus 55
Option B
C
70 less-than-or-equal-to t + 55
Option C
D
70 greater-than t + 55
Option D
2
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Ben wants to buy a new car stereo and he has already saved some money. He used this inequality to represent the amount he still has to save to be able to buy the stereo, where a represents the amount still left to save. If Ben saves $15 a week for the next 10 weeks, will he be able to buy the stereo and why?

Question illustration
A
No, because he needs to save at least $153, and he will only save $150 over the next ten weeks.
B
No, because he needs to save $577, and he will only save $150 more.
C
Yes, because he has already saved $365, and the stereo cost $212.
D
Yes, because he has already saved $212, and he will save another $150.
3

Which inequality has –12 in its solution set?ABCD

Question illustration
A
A
B
B
C
C
D
D
4

Aisha needs to be at least 48 inches tall to ride the colossal coaster at the amusement park. If she grows 5 inches during the next year, Aisha will still not be tall enough to ride. In the context of this situation, what does the inequality represent?

Question illustration
A
After next year, Aisha still needs to grow 43 more inches to ride.
B
Aisha is less than 43 inches tall right now.
C
Aisha needs to grow 43 more inches to ride.
D
Aisha is at least 43 inches tall now.
5

Vince is saving for a new mobile phone. The least expensive model Vince likes costs $225.90. Vince has saved $122.35. He used this solution to determine how much more he needs to save. Vince says that based on the solution, he should save a maximum of $103.55.Is Vince correct?

Question illustration
A
Vince is correct because he found the correct solution to the inequality.
B
Vince is correct because he should save at least $103.55.
C
Vince is not correct because he wrote the wrong inequality to represent the situation.
D
Vince is not correct because he should have interpreted the solution as having to save a minimum of $103.55.
6

A clothing store offers a free T-shirt when a customer spends $75 or more. Lyndon has already spent $36.95. Which statement best represents all of the amounts he can spend to get a free T-shirt?

A
$34.05 or more
B
$34.05 or less
C
$38.05 or more
D
$38.05 or less
7

Which is the solution to the inequality?

Question illustration
A
y less-than negative 12
Option A
B
y greater-than negative 12
Option B
C
y less-than 18
Option C
D
y greater-than 18
Option D
8

Clarissa has a budget of $1,200 a month to spend for rent and food. She has already spent $928 this month. Which inequality represents the amount she can still spend this month and remain within her budget?

A
x greater-than 272
Option A
B
x less-than-or-equal-to 272
Option B
C
x less-than 272
Option C
D
x greater-than-or-equal-to 272
Option D
9

Tyrese’s sister is 41 inches tall. A ride at the amusement park states that riders must be at least 52 inches tall to ride. Which statements describe how much taller Tyrese’s sister must be to ride? Select two options.

A
at least 11 inches
B
no more than 11 inches
C
a maximum of 11 inches
D
a minimum of 11 inches
E
fewer than 11 inches
10

Which shows the correct solution to the inequality ?

Question illustration
A
StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 7 over 10 EndFraction minus 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 28 over 40 EndFraction minus 1 and StartFraction 25 over 40 EndFraction greater-than-or-equal-to p. p less-than-or-equal-to negative 1 and StartFraction 3 over 40 EndFraction.
Option A
B
StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 7 over 10 EndFraction minus 1 and StartFraction 5 over 8 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction minus 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 28 over 40 EndFraction minus 1 and StartFraction 25 over 40 EndFraction greater-than-or-equal-to p. p greater-than-or-equal-to negative 1 and StartFraction 3 over 40 EndFraction.
Option B
C
StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 7 over 10 EndFraction minus 1 and StartFraction 5 over 8 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction minus 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 28 over 40 EndFraction minus 1 and StartFraction 25 over 40 EndFraction greater-than-or-equal-to p. p less-than-or-equal-to negative StartFraction 37 over 40 EndFraction.
Option C
D
StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 7 over 10 EndFraction minus 1 and StartFraction 5 over 8 EndFraction greater-than-or-equal-to 1 and StartFraction 5 over 8 EndFraction minus 1 and StartFraction 5 over 8 EndFraction + p. StartFraction 28 over 40 EndFraction minus 1 and StartFraction 25 over 40 EndFraction greater-than-or-equal-to p. p greater-than-or-equal-to negative StartFraction 37 over 40 EndFraction.
Option D

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