AnswersFL-1200330-Algebra 2 Sem 1 - FlexAddition and Subtraction of PolynomialsQuestion 4
4
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Addition and Subtraction of Polynomials

Question 4 • FL-1200330-Algebra 2 Sem 1 - Flex

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) = a2 + ab + ( b2)

Answer
(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

2

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

9

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

-7

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