AnswersINMT3 Integrated Math 3 Sem 1 26-27Addition and Subtraction of PolynomialsQuestion 2
2
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Addition and Subtraction of Polynomials

Question 2 • [INMT3] Integrated Math 3 Sem 1 (26-27)

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) = a2 + ab + ( b2)

Answer
(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

2

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

9

(5a2 + 4ab – 3b2) – (–5ab + 4b2 + 3a2) =:

-7

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