Answers NJ-Algebra I CRSolving Linear Equations: Variables on Both Sides

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On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9).

(–9, 0)

(–3, 0)

(0, –9)

(0, –3)

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On a coordinate plane, a curved line with minimum values of (negative 1.5, negative 2) and (1.5, 2), and a maximum value of (0, 4), crosses the x-axis at (negative 2, 0), (negative 1, 0), (1, 0), and (2, 0), and crosses the y-axis at (0, 4).

(0, 4)

(–1, 0)

(4, 0)

(0, –1)

On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3) crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3).

F(x) < 0 over the interval (–∞, –4)

F(x) < 0 over the interval (–∞, –3)

F(x) > 0 over the interval (–∞, –3)

F(x) > 0 over the interval (–∞, –4)

On a coordinate plane, a curved line with a minimum value of (0.8, negative 11.4) and maximum values of (negative 1.6, 56) and (2, 0), crosses the x-axis at (negative 2.5, 0), (0, 0), and (2, 0), and crosses the y-axis at (0, 0).

–11.4

On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (1.05, negative 41), and a maximum value of (negative 0.5, 5), crosses the x-axis at (negative 2, 0), (0, 0), and (1.5, 0), and crosses the y-axis at (0, 0).

As the x-values go to positive infinity, the function’s values go to positive infinity.

As the x-values go to zero, the function’s values go to positive infinity.

As the x-values go to negative infinity, the function’s values are equal to zero.

As the x-values go to negative infinity, the function’s values go to negative infinity.

On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0), and crosses the y-axis at (0, negative 3).

x-intercept = (–1, 0)y-intercept = (–3, 0)

x-intercept = (0, –1)y-intercept = (0, –3)

x-intercept = (0, –1)y-intercept = (–3, 0)

x-intercept = (–1, 0)y-intercept = (0, –3)

On a coordinate plane, a curved line with a minimum value of (negative 1.25, negative 3.25) and a maximum value of (0.25, negative 1.75), crosses the x-axis at (negative 2.25, 0), and crosses the y-axis at (0, negative 2). The line exits the plane at (negative 2.75, 6) and (1.5, 6).

As the x-values go to positive infinity, the function's values go to negative infinity.

As the x-values go to zero, the function's values go to positive infinity.

As the x-values go to negative infinity, the function's values are equal to zero.

As the x-values go to positive infinity, the function's values go to positive infinity.

On a coordinate plane, a curved line with a minimum value of (1, negative 4) crosses the x-axis at (negative 1, 0), and (3, 0), and crosses the y-axis at (0, negative 3).

(0, –3)

(–1, 0) and (3, 0)

(0, –1) and (0, 3)

(–1, 0), (3, 0), and (0, –3)

On a coordinate plane, a curved line with minimum values of (negative 0.8, negative 2.8) and (3, 0), and a maximum value of (1.55, 10.8), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0).

[–3, –2]

[–2, 0]

[0, 2]

[2, 4]

Which function is positive for the entire interval [–3, –2]?

Option

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