Answers MO-Algebra I AEvaluating Functions

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On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 0.25). The line exits the plane at (negative 2, negative 6) and (2, 6).

As the x-values go to positive infinity, the function's values go to negative infinity.

As the x-values go to zero, the function's values go to positive infinity.

As the x-values go to negative infinity, the function's values are equal to zero

As the x-values go to positive infinity, the function's values go to positive infinity.

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On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), crosses the x-axis at (negative 0.7, 0), (0.76, 0), and (2.5, 0), and crosses the y-axis at (0, 2).

F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5).

F(x) > 0 over the intervals (-∞, -0.7) and (0.76, 2.5).

F(x) < 0 over the intervals (-0.7, 0.76) and (2.5, ∞).

F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞).

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9).

(–9, 0)

(–3, 0)

(0, –9)

(0, –3)

On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3) crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3).

F(x) < 0 over the interval (–∞, –4)

F(x) < 0 over the interval (–∞, –3)

F(x) > 0 over the interval (–∞, –3)

F(x) > 0 over the interval (–∞, –4)

On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0), and crosses the y-axis at (0, negative 3).

x-intercept = (–1, 0)y-intercept = (–3, 0)

x-intercept = (0, –1)y-intercept = (0, –3)

x-intercept = (0, –1)y-intercept = (–3, 0)

x-intercept = (–1, 0)y-intercept = (0, –3)

On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (1.05, negative 41), and a maximum value of (negative 0.5, 5), crosses the x-axis at (negative 2, 0), (0, 0), and (1.5, 0), and crosses the y-axis at (0, 0).

As the x-values go to positive infinity, the function’s values go to positive infinity.

As the x-values go to zero, the function’s values go to positive infinity.

As the x-values go to negative infinity, the function’s values are equal to zero.

As the x-values go to negative infinity, the function’s values go to negative infinity.

On a coordinate plane, a curved line with minimum values of (negative 0.5, negative 7) and (2.5, negative 1), and a maximum value of (1.5, 1), crosses the x-axis at (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 6).

[–1, 0]

[1, 2]

[2, 3]

[3, 4]

On a coordinate plane, a curved line with minimum values of (negative 1.5, negative 2) and (1.5, 2), and a maximum value of (0, 4), crosses the x-axis at (negative 2, 0), (negative 1, 0), (1, 0), and (2, 0), and crosses the y-axis at (0, 4).

(0, 4)

(–1, 0)

(4, 0)

(0, –1)

On a coordinate plane, a curved line with a minimum value of (5.1, negative 7) and a maximum value of (0, 25), crosses the x-axis at (negative 3.4, 0), (3.9, 0), and (6, 0), and crosses the y-axis at (0, 25).

Over the interval [–4, –2], the local minimum is 0.

Over the interval [–2, –1], the local minimum is 25.

Over the interval [–1, 4], the local minimum is 0.

Over the interval [4, 7], the local minimum is -7.

Which function is positive for the entire interval [–3, –2]?

Option

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