An air pump does 5,600 J of work to launch a water bottle rocket into the air. If the air pump applies 150 N of force to the rocket at an angle of 45° to the ground, what is the horizontal distance the water bottle rocket travels? Round your answer to two significant figures.

Work equals force times displacement in the direction of the force. Since the force is at 45° to the ground, its horizontal component is 150 cos 45° ≈ 106 N. The horizontal distance is 5,600 J ÷ 106 N ≈ 53 m, or 5.3 × 10¹ m, so the answer is choice B.

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