AnswersAZ-Intermediate Algebra A MA311Solving Linear Equations: Distributive Property

Solving Linear Equations: Distributive Property Answers

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1
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Use the drops-downs to justify how Heidi arrived at each step. Step 1: Step 2: Step 3: Step 4: Step 5:

Answers:
Selection 1:distributive property
Selection 2:combine like terms
Selection 3:subtraction property of equality
Selection 4:addition property of equality
Selection 5:division property of equality
3

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Answer not available
4

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Answer not available
5

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Answer not available
7

Which of these equations have no solution? Check all that apply.

A
2(x + 2) + 2 = 2(x + 3) + 1
B
2x + 3(x + 5) = 5(x – 3)
C
4(x + 3) = x + 12
D
4 – (2x + 5) = (–4x – 2)
Option D
E
5(x + 4) – x = 4(x + 5) – 1
8

Which equation is an identity?

A
3(x – 1) = x + 2(x + 1) + 1
B
x – 4(x + 1) = –3(x + 1) + 1
C
2x + 3 = (4x + 2) + 2
Option C
D
(6x – 3) = 3(x + 1) – x – 2
Option D
10

Which best describes Nosaira’s work and answer?

A
Her work is correct, but there is one solution rather than no solution.
B
Her work is correct and her interpretation of the answer is correct.
C
Her work is incorrect. She distributed incorrectly.
D
Her work is incorrect. She moved terms across the equals sign incorrectly.
11

Leena consumes 400 calories at breakfast and 350 calories at lunch. She consumes of her daily calories at dinner. If x represents the calories consumed at dinner, which statements describe the situation? Check all that apply.

Question illustration
A
Leena consumed 1,500 calories at dinner.
B
The equation (x + 400 + 350) = x can be used to model the situation.
Option B
C
Leena consumed 500 calories at dinner.
D
The equation (x) = x(400 + 300) can be used to model the situation.
Option D
E
Leena consumed 1,000 calories at dinner.
F
The equation x(400 + 300) = x can be used to model the situation.
Option F

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