Rational Equations

Question 1

Solve: The solution is a =

Revolt · Accepted Answer

1/6

Question 2

Solve and check The solution is c =

Revolt · Accepted Answer

14

Question 3

After multiplying each side of the equation by the LCD and simplifying, the resulting equation is 3x² – 20x + 12 = 03x² – 20x – 12 = 0✔ 3x² + 20x + 12 = 03x² + 20x – 12 = 0.

Revolt · Accepted Answer

C: 3x² + 20x + 12 = 0

Question 4

Solve and check: 1 x + 3 = x + 10 x − 2 From least to greatest, the solutions are x = and x = .

Revolt · Accepted Answer

Part 1: -8; Part 2: -4

Question 5

x = 1 is a solution.x = 0 is a solution.x = –1 is a solution.x = –6 is a solution.

Revolt · Accepted Answer

A: x = 1 is a solution.; C: x = –1 is a solution.

Question 6

mc001-1.jpg

Revolt · Accepted Answer

C:

Question 7

Question 7

Revolt · Accepted Answer

No, the student is incorrect. While solving the equation algebraically results in the value 2, this value is an extraneous solution. If you substitute 2 back into the original equation, the denominators (a  2) and (a^2  4) both become zero. Since division by zero is undefined, 2 cannot be a solution, and the equation actually has no solution.

Question 8

mc001-1.jpg

Revolt · Accepted Answer

B: mc001-2.jpg

Question 9

How many extraneous solutions are there?✔ zeroonetwo

Revolt · Accepted Answer

A: zero

Question 10

What are the solutions to the equation?

Revolt · Accepted Answer

A:

Rational Equations Answers

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