Question 9 • Algebra III A
Correct Answer:
To graph y ≤ -x^2 + 2x, first graph the boundary parabola y = -x^2 + 2x. The parabola opens downward because the leading coefficient is negative. Find the vertex by using x = -b/(2a) = -2/(2*-1) = 1; the vertex is at (1, 1). The x-intercepts are at x=0 and x=2. Use a solid line for the boundary because the inequality is 'less than or equal to'. Finally, test a point like (1, 0). Since 0 ≤ -1^2 + 2(1) (0 ≤ 1) is true, shade the region inside the parabola.