Question 17 • MO-Algebra II A-CR
Subtract by changing the signs of the second complex number: (–9 – 8i) – (3 + 2i) = –9 – 8i – 3 – 2i. Combine the real parts and the imaginary parts: –9 – 3 = –12 and –8i – 2i = –10i. The result is –12 – 10i, choice C.
AI-written and checked against the verified answer.