AnswersAlgebra III ASimplifying Polynomial Expressions

Simplifying Polynomial Expressions Answers

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f (x) has two real roots and one imaginary root.f (x) has three real roots.f (x) has five real roots.f (x) has three real roots and two imaginary roots.

A
f (x) has two real roots and one imaginary root.
B
f (x) has three real roots.
C
f (x) has five real roots.
D
f (x) has three real roots and two imaginary roots.
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Use the fundamental theorem of algebra and the complex conjugate theorem to determine the number and nature of the remaining root(s). Explain your thinking.

Answer:

The polynomial is degree 3, so it has three roots counting multiplicity. Two roots are given, leaving one remaining root. If the given roots are non-real complex conjugates, the remaining root must be real, since non-real roots occur in conjugate pairs.

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Did you include the following in your response?

A
The degree of the polynomial is 3.
B
By the fundamental theorem of algebra, the function has three roots.
C
Two roots are given, so there must be one root remaining.
D
By the complex conjugate theorem, imaginary roots come in pairs.
E
The final root must be real.

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