Question 16 • AL-Algebra I with Probability Critical Standards
The squared term is defined for every real x, so the domain is all real numbers. The graph has vertex (-1, 2), making its minimum value 2; therefore its range is y ≥ 2, not y ≥ 1. At x = 0, f(0) = (0 + 1)² + 2 = 3, so the y-intercept is 3. The graph shifts 1 unit left and 2 units up, and it has no x-intercepts.
AI-written and checked against the verified answer.