Question 13 • Applications and Modeling
At 8:00 a.m., the temperature was 79°F, and at 11:00 a.m., it was 92°F. The average rate of change is (92 − 79) ÷ (11 − 8) = 13 ÷ 3 ≈ 4.33°F per hour, so the correct choice is 4.33°.
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