A gas has an initial volume of 212 cm cubed at a temperature of 293 cap k and a pressure of 0 point 9 8 atm What is the final pressure of the gas if the volume decreases to 196 cm cubed and the temperature of the gas increases to 308 cap k ?

Use the combined gas law: P₁V₁/T₁ = P₂V₂/T₂. Solving for the final pressure gives P₂ = (0.98 atm × 212 cm³ × 308 K) ÷ (293 K × 196 cm³) ≈ 1.11 atm. Rounded to two significant figures, the pressure is 1.1 atm, choice A.

AI-written and checked against the verified answer.