A gas has an initial volume of 212 cm3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm3 and the temperature of the gas increases to 308 K?

Use the combined gas law: P₁V₁/T₁ = P₂V₂/T₂. Solving gives P₂ = (0.98 atm × 212 cm³ × 308 K)/(293 K × 196 cm³) ≈ 1.12 atm, which rounds to 1.1 atm. The correct choice is D, 1.1 atm.

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