AnswersCR27 ALG 1-1200310-S2-Degele-VOL7006PChapter 9 Unit TEST: Solving Quadratic Equations

Chapter 9 Unit TEST: Solving Quadratic Equations Answers

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What are the solutions to m2 – 9 = 0?

A
m = –9 and m = 0
B
m = –3 and m = 3
C
m = –3
D
m = 9
2
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A quadratic equation has zero real number solutions. Which could be the discriminant value associated with this equation?

A
–5
B
0
C
1
D
6
3

Two sandboxes with the same area are shown.The equation represents the area of Sandbox 2 in terms of its width.

Question illustration
A
2.72 meters
B
3.06 meters
C
9.16 meters
D
10.18 meters
4

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0?

A
x = –6 or x =
Option A
B
x = –4 or x =
Option B
C
x = or x = 6
Option C
D
x = or x = 4
Option D
5

Using the Completing the Square method, what are the zeros of the quadratic function f(x) = 2x2 + 8x – 3?

A
x = –2 – and x = –2 +
Option A
B
x = –2 – and x = –2 +
Option B
C
x = 2 – and x = 2 +
Option C
D
x = 2 – and x = 2 +
Option D
6

Mariya is solving the quadratic equation by completing the square.4x2-20x+3=04x2-20x=-3A(x2-5x)=-3

A
-20
B
3
C
4
D
5
7

Heather is writing a quadratic function that represents a parabola that touches but does not cross the x-axis at x = –6. Which function could Heather be writing?

A
f(x) = x2 + 36x + 12
B
f(x) = x2 – 36x – 12
C
f(x) = –x2 + 12x + 36
D
f(x) = –x2 – 12x – 36
8

A rectangle’s length is 5 inches more than twice its width. Its area is 50 square inches. Which equation can be used to find its width, w?

A
2w(2w + 5) = 50
B
2w(w + 5) = 50
C
w(2w + 5) = 50
D
w(w + 5) = 50
9

What values of b satisfy 4(3b + 2)2 = 64?

A
b = and b = –2
Option A
B
b = 2 and b =
Option B
C
b = and b = 3
Option C
D
b = 2 and b =
Option D
10

Solve x2 + 6x = 7 by completing the square. Which is the solution set of the equation?

A
{–7, 1}
B
(negative 3 minus StartRoot 10 EndRoot comma negative 3 + StartRoot 10 EndRoot)
Option B
C
(3 minus StartRoot 10 EndRoot comma negative 3 + StartRoot 10 EndRoot)
Option C
D
{1, 7}
11

Clara writes the equation (x – 13)(x + 8) = 196 to solve for the missing side length of a rectangle represented by the factor x + 8. What is the missing side length represented by x + 8 units of the rectangle?

A
7
B
15
C
20
D
28
12

Solve x2 – 8x = 20 by completing the square. Which is the solution set of the equation?

A
{–22, 14}
B
{–14, 22}
C
{–10, 2}
D
{–2, 10}
13

Fiona is completing the square to solve the polynomial equation.x2 – 4x + 1 = 0

A
isolating the constant 1
B
adding 4 to both sides of the equation
C
isolating the second term, –4x
D
adding 1 to both sides of the equation
14

The product of two consecutive integers is 272. Which quadratic equation can be used to find x, the smaller number?

A
x2 + 1 = 272
B
x2 − 1 = 272
C
x2 + x − 272 = 0
D
x2 + x + 272 = 0
15

A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

A
0 = 2x2 – 4x + 1
B
0 = 2x2 – 5x + 3
C
0 = –2x2 – 4x – 2
D
0 = –2x2 – 3x – 1

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Chapter 9 Unit TEST: Solving Quadratic Equations…