Chemical Bonding and Reactions — Test

Question 5 • Chemistry

Consider the following reversible reaction. CO times g plus 2 cap h sub 2 g long left right arrow CH sub 3 OH g What is the equilibrium constant expression for the given system?

Answer

cap k sub e q is equal to the fraction with numerator open paren CH sub 3 OH close paren and denominator CO times open bracket cap h sub 2 close bracket

cap k sub e q is equal to the fraction with numerator open paren CH sub 3 OH close paren and denominator CO times open bracket cap h sub 2 close bracket squared

cap k sub e q is equal to the fraction with numerator CO times open bracket cap h sub 2 close bracket squared and denominator open paren CH sub 3 OH close paren

cap k sub e q is equal to the fraction with numerator CO times open bracket cap h sub 2 close bracket and denominator open paren CH sub 3 OH close paren

Explanation

For a reaction, the equilibrium constant expression places product concentrations in the numerator and reactant concentrations in the denominator. Each concentration is raised to the power of its coefficient in the balanced equation. Thus, for CO(g) + 2 H₂(g) ⇌ CH₃OH(g), Kₑq = [CH₃OH]/([CO][H₂]²), which is choice D.

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