Consider the chemical equation. 2 cap h sub 2 plus cap o sub 2 rightarrow 2 cap h sub 2 cap o What is the percent yield of cap h sub 2 cap o if 87 point 0 g of cap h sub 2 cap o is produced by combining 95 point 0 g of cap o sub 2 and 11 point 0 g of cap h sub 2 ? Use percent Yield is equal to Actual yield over Theoretical yield times 100

First identify the limiting reactant. The 11.0 g of H₂ is about 5.46 mol, which can produce about 5.46 mol of H₂O because the equation has a 2:2 ratio. That corresponds to a theoretical yield of 5.46 × 18.0 ≈ 98.3 g H₂O; the O₂ is in excess. Percent yield = (87.0 g ÷ 98.3 g) × 100 ≈ 88.5%, so the correct choice is 88.5 percent.

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