Consider the chemical equation. 2 NBr sub 3 plus 3 NaOH rightarrow cap n sub 2 plus 3 NaBr plus 3 HOBr If there are 40 mol of NBr sub 3 and 48 mol of NaOH , what is the excess reactant?

The balanced equation requires 3 mol NaOH for every 2 mol NBr₃. For 40 mol NBr₃, the required NaOH is 40 × (3/2) = 60 mol, but only 48 mol is available. Therefore, NaOH is the limiting reactant and NBr₃ is in excess; the correct choice is NBr₃.

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