Amira is solving the equation x squared minus 6 x is equal to 1 Which value must be added to both sides of the equation to make the left side a perfect-square trinomial?

To make x² − 6x a perfect-square trinomial, take half of the coefficient of x and square it: (−6 ÷ 2)² = 9. Adding 9 to both sides gives x² − 6x + 9 = 1 + 9, and the left side factors as (x − 3)². So the value is 9, choice C.

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