What are the coordinates of the vertex of the function f(x) = x2 − 12x + 5?

For a quadratic function ax² + bx + c, the vertex’s x-coordinate is −b/(2a). Here a = 1 and b = −12, so x = 12/2 = 6. Substituting gives f(6) = 6² − 12(6) + 5 = 36 − 72 + 5 = −31, so the vertex is (6, −31), choice C.

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