Completing The Square Answers
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1
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Solve for in the equation .
A
x = –12 or x = 2B
x = –11 or x = 1C
x = –2 or x = 12D
x = –1 or x = 112
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What are the solutions of ?
A
or
B
or
C
or
D
or
3
Solve for in the equation .
A
x = –6 or x = 2B
x = negative 2 plus-or-minus 2 StartRoot 2 EndRoot
C
x = –2 or x = 6D
x = 2 plus-or-minus 2 StartRoot 2 EndRoot
4
Solve for in the equation .
A
x = negative 6 plus-or-minus StartRoot 82 EndRoot
B
x = negative 6 plus-or-minus 2 StartRoot 17 EndRoot
C
x = 1 plus-or-minus StartRoot 33 EndRoot
D
x = 1 plus-or-minus StartRoot 47 EndRoot
5
Solve for in the equation .
A
x = 2 plus-or-minus StartRoot 42 EndRoot
B
x = 2 plus-or-minus StartRoot 33 EndRoot
C
x = 2 plus-or-minus StartRoot 34 EndRoot
D
x = 4 plus-or-minus StartRoot 42 EndRoot
6
What are the solution(s) of ?
A
or
B
or
C
x = 2
D
x = 4
7
Brian is solving the equation . What value must be added to both sides of the equation to make the left side a perfect-square trinomial?
A
StartFraction 9 Over 64 EndFraction
B
StartFraction 9 Over 16 EndFraction
C
Three-fourths
D
Nine-fourths
8
Solve for in the equation .
A
x = five-halves plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
B
x = five-halves plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
C
x = five-fourths plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
D
x = five-fourths plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
9
What are the solution(s) of ?
A
orB
orC
x = 2D
x = 410
Solve for in the equation .
A
x = –16 or x = –4B
x = –10C
x = –8D
x = 4 or x = 16Did you find these answers helpful?
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