AnswersMathematics III ACompleting The Square

Completing The Square Answers

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Solve for in the equation .

Question illustration
A
x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i
Option A
B
x = –7 ± 8i
C
x = 7 plus-or-minus 4 StartRoot 6 EndRoot i
Option C
D
x = 7 ± 8i
3

Solve for in the equation .

Question illustration
A
x = –12 or x = 2
B
x = –11 or x = 1
C
x = –2 or x = 12
D
x = –1 or x = 11
4

Solve for in the equation .

Question illustration
A
x = negative 1 plus-or-minus StartRoot 15 EndRoot
Option A
B
x = negative 1 plus-or-minus StartRoot 17 EndRoot
Option B
C
x = negative 2 plus-or-minus 2 StartRoot 5 EndRoot
Option C
D
x = negative 1 plus-or-minus StartRoot 13 EndRoot
Option D
5

Brian is solving the equation . What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

Question illustration
A
StartFraction 9 Over 64 EndFraction
Option A
B
StartFraction 9 Over 16 EndFraction
Option B
C
Three-fourths
Option C
D
Nine-fourths
Option D
6

Solve for in the equation .

Question illustration
A
x = negative 1 plus-or-minus StartRoot 15 EndRoot
Option A
B
x = negative 1 plus-or-minus StartRoot 17 EndRoot
Option B
C
x = negative 2 plus-or-minus 2 StartRoot 5 EndRoot
Option C
D
x = negative 1 plus-or-minus StartRoot 13 EndRoot
Option D
7

Solve for in the equation .

Question illustration
A
x = –6 or x = 2
B
x = negative 2 plus-or-minus 2 StartRoot 2 EndRoot
Option B
C
x = –2 or x = 6
D
x = 2 plus-or-minus 2 StartRoot 2 EndRoot
Option D
9

Solve for in the equation .

Question illustration
A
x = five-halves plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
Option A
B
x = five-halves plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
Option B
C
x = five-fourths plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
Option C
D
x = five-fourths plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
Option D
10

Solve for in the equation .

Question illustration
A
x = negative 12 plus-or-minus StartRoot 85 EndRoot
Option A
B
x = negative 6 plus-or-minus StartRoot 23 EndRoot i
Option B
C
x = 6 plus-or-minus StartRoot 23 EndRoot i
Option C
D
x = 12 plus-or-minus StartRoot 85 EndRoot
Option D

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