AnswersMathematics III ASolving Quadratic Equations by Factoring

Completing The Square Answers

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1
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Solve for in the equation .

Question illustration
A
x = 5 plus-or-minus 2 StartRoot 5 EndRoot
Option A
B
x = 5 plus-or-minus StartRoot 35 EndRoot
Option B
C
x = 10 plus-or-minus 2 StartRoot 5 EndRoot
Option C
D
x = 10 plus-or-minus StartRoot 35 EndRoot
Option D
2
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Solve for in the equation .

Question illustration
A
x = five-halves plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
Option A
B
x = five-halves plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
Option B
C
x = five-fourths plus-or-minus StartFraction StartRoot 29 EndRoot Over 2 EndFraction
Option C
D
x = five-fourths plus-or-minus StartFraction StartRoot 41 EndRoot Over 4 EndFraction
Option D
3

Which value must be added to the expression x2 + 12x to make it a perfect-square trinomial?

A
6
B
36
C
72
D
144
4

Solve for in the equation .

Question illustration
A
x = negative 6 plus-or-minus StartRoot 82 EndRoot
Option A
B
x = negative 6 plus-or-minus 2 StartRoot 17 EndRoot
Option B
C
x = 1 plus-or-minus StartRoot 33 EndRoot
Option C
D
x = 1 plus-or-minus StartRoot 47 EndRoot
Option D
5

Solve for in the equation .

Question illustration
A
x = negative 1 plus-or-minus StartRoot 15 EndRoot
Option A
B
x = negative 1 plus-or-minus StartRoot 17 EndRoot
Option B
C
x = negative 2 plus-or-minus 2 StartRoot 5 EndRoot
Option C
D
x = negative 1 plus-or-minus StartRoot 13 EndRoot
Option D
6

Solve for in the equation .

Question illustration
A
x = negative 12 plus-or-minus StartRoot 85 EndRoot
Option A
B
x = negative 6 plus-or-minus StartRoot 23 EndRoot i
Option B
C
x = 6 plus-or-minus StartRoot 23 EndRoot i
Option C
D
x = 12 plus-or-minus StartRoot 85 EndRoot
Option D
7

Which value must be added to the expression x2 + x to make it a perfect-square trinomial?

A
One-fourth
Option A
B
One-half
Option B
C
1
D
4
8

Solve for in the equation .

Question illustration
A
x = 2 plus-or-minus StartRoot 42 EndRoot
Option A
B
x = 2 plus-or-minus StartRoot 33 EndRoot
Option B
C
x = 2 plus-or-minus StartRoot 34 EndRoot
Option C
D
x = 4 plus-or-minus StartRoot 42 EndRoot
Option D
9

Solve for in the equation .

Question illustration
A
x = –12 or x = 2
B
x = –11 or x = 1
C
x = –2 or x = 12
D
x = –1 or x = 11
10

Solve for in the equation .

Question illustration
A
x = –6 or x = 2
B
x = negative 2 plus-or-minus 2 StartRoot 2 EndRoot
Option B
C
x = –2 or x = 6
D
x = 2 plus-or-minus 2 StartRoot 2 EndRoot
Option D

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