What are the coordinates of the vertex of the function f(x)=x2+10x−3?

For f(x) = x² + 10x − 3, the vertex’s x-coordinate is −b/(2a) = −10/(2·1) = −5. Substituting −5 gives f(−5) = 25 − 50 − 3 = −28, so the vertex is (−5, −28), choice A.

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