Compositions Answers

Trapezoid G H J K is rotated about G 90 degrees counterclockwise to form trapezoid G prime H prime J prime K prime. Trapezoid G prime H prime J prime K prime is reflected across the line of reflection m to form trapezoid G double-prime H double-prime J double-prime K double-prime.

A composition of transformations maps ΔXYZ to ΔX"Y"Z".

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7).

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Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime F prime G prime H prime is shifted down to E double-prime F double-prime G double-prime H double-prime.

On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime has points (negative 1, 4), (negative 1, 2), (negative 5, 3). Triangle B double-prime C double-prime D double-prime has points (5, negative 1), (5, negative 3), (1, negative 2).

Parallelogram P Q R S is rotated about point Q 180 degrees to form parallelogram P prime Q prime R prime S prime. Parallelogram P prime Q prime R prime S prime is reflected across line of reflection l to form parallelogram P double-prime Q double-prime Q double-prime S double-prime.

The rule is applied to ΔABC.

Triangle A B C is reflected across the line of reflection m to form triangle A prime B prime C prime. Triangle A prime B prime C prime is rotated about point B prime 270 degrees to form triangle A double-prime B double-prime C double-prime.