Compositions Answers

Square A"B"C"D" is the final image after the rule was applied to square ABCD.

Trapezoid G H J K is rotated about G 90 degrees counterclockwise to form trapezoid G prime H prime J prime K prime. Trapezoid G prime H prime J prime K prime is reflected across the line of reflection m to form trapezoid G double-prime H double-prime J double-prime K double-prime.

The rule is applied to ΔABC.

The rule is applied to ΔFGH to produce ΔF"G"H".

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7).

A composition of transformations maps ΔXYZ to ΔX"Y"Z".

Parallelogram F"G"H"J" is the final image after the rule was applied to parallelogram FGHJ.

On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime has points (negative 1, 4), (negative 1, 2), (negative 5, 3). Triangle B double-prime C double-prime D double-prime has points (5, negative 1), (5, negative 3), (1, negative 2).

Question text not available

On a coordinate plane, 2 triangles are shown. Triangle J K L has points (2, negative 4), (5, negative 4), (2, negative 2). Triangle J double-prime K double-prime L double-prime has points (2, 2), (2, 5), (0, 2).