Compositions Answers

On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime has points (negative 1, 4), (negative 1, 2), (negative 5, 3). Triangle B double-prime C double-prime D double-prime has points (5, negative 1), (5, negative 3), (1, negative 2).

Parallelogram F"G"H"J" is the final image after the rule was applied to parallelogram FGHJ.

Which ordered pairs name the coordinates of vertices of the pre-image, trapezoid ABCD? Select two options.

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On a coordinate plane, 3 parallelograms are shown. Parallelogram A B C D has points (3, 5), (6, 5), (4, 1), (1, 1). Parallelogram A prime B prime C prime D prime has points (3, negative 5), (6, negative 5), (4, negative 1), (1, negative 1). Parallelogram A double-prime B double-prime C double-prime D double-prime has points (negative 3, negative 4), (0, negative 4), (negative 2, 0), (negative 4, 0).

Trapezoid G H J K is rotated about G 90 degrees counterclockwise to form trapezoid G prime H prime J prime K prime. Trapezoid G prime H prime J prime K prime is reflected across the line of reflection m to form trapezoid G double-prime H double-prime J double-prime K double-prime.

Figure WXYZ is transformed using the rule . Point W of the pre-image is at (1, 6).

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7).

Square A"B"C"D" is the final image after the rule was applied to square ABCD.

The rule is applied to ΔFGH to produce ΔF"G"H".