Conditional Probability

Question 1

What statements are correct? Check all that apply.The conditional probability formula is P(X │ Y) = .The conditional probabilities P(D │ N) and P(N │ D) are equal for any events D and N.The notation P(R │ S) indicates the probability of event R, given that event S has already occurred.Conditional probability applies only to independent events.Conditional probabilities can be calculated using a Venn diagram.

Revolt · Accepted Answer

A: The conditional probability formula is P(X │ Y) = .; C: The notation P(R │ S) indicates the probability of event R, given that event S has already occurred.; E: Conditional probabilities can be calculated using a Venn diagram.

Question 2

Given that a randomly chosen student participates in band, what is the probability that the student also participates in track?

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B:

Question 3

What is the probability that a randomly chosen tenth-grader is male? [___]

Revolt · Accepted Answer

D: 80/154

Question 4

A dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 percent brush at least twice a day and floss daily. What is the probability that a patient flosses daily, given that he or she brushes at least twice a day? Round to the nearest percent.16%23%40%57%

Revolt · Accepted Answer

B: 23%

Question 5

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second.

Revolt · Accepted Answer

P(B) =: 8/12; P(R | B) =: 4/11; P(B ∩ R) =: 8/33; The probability that the first ball chosen is black and the second ball chosen is red is about percent.: 24

Question 6

P(B) = [___]

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C: 8/12

Question 7

Question 7

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A: 5%

Question 8

[___]

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12/35

Question 9

Elias writes the numbers 1 through 20 on separate slips of paper. There are 16 white slips of paper and four yellow slips of paper. There are eight odd numbers on white slips, and the rest of the odd numbers are on yellow slips. Are the events "odd” and "yellow” independent?no, because the probability of choosing a yellow slip is not equal to the probability of choosing a yellow slip given an odd numberno, because the probability of choosing an odd number is not equal to the probability of choos

Revolt · Accepted Answer

C: yes, because the probability of choosing an odd number is equal to the probability of choosing an odd number given that the slip is yellow

Question 10

Which conditional probabilities are correct? Check all that apply.P(D | F) = P(E | D) = P(D | E) = P(F | E) = P(E | F) =

Revolt · Accepted Answer

Conditional Probability Answers

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