What is the radius and center of a circle with the equation (x – 2)2 + (y – 3)2 = 36?

A circle in standard form is (x − h)² + (y − k)² = r², with center (h, k) and radius r. Comparing the equation to this form gives h = 2, k = 3, and r² = 36, so the radius is 6 units. Therefore, the center is (2, 3) and the radius is 6 units, choice A.

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