Cumulative Exam — Cumulative exam Answers

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A statistics student wants to survey a high school of 910 students concerning support for increasing the number of student parking spots. The student randomly selects 90 students, and finds that 63 support increasing the number of student parking spots. Assuming the conditions for inference have been met, what is the 95% confidence interval for the true proportion of students who would support the increase in the number of parking spots?

A
0.30 plus-or-minus 1.65 StartRoot StartFraction 0.30 (1 minus 0.30) Over 90 EndFraction EndRoot
Option A
B
0.70 plus-or-minus 1.65 StartRoot StartFraction 0.70 (1 minus 0.70) Over 910 EndFraction EndRoot
Option B
C
0.30 plus-or-minus 1.96 StartRoot StartFraction 0.30 (1 minus 0.30) Over 910 EndFraction EndRoot
Option C
D
0.70 plus-or-minus 1.96 StartRoot StartFraction 0.70 (1 minus 0.70) Over 90 EndFraction EndRoot
Option D
43

A math teacher is investigating the problem of students losing their graphing calculators because their names aren’t written on them. In a random sample of 50 students, only 32 had their names written on their graphing calculators. The teacher constructs a 99% confidence interval for the proportion of all students at this school who have their names written on their graphing calculators and obtains (0.465, 0.815). What is the correct interpretation of this confidence interval?

A
The teacher can be 99% confident that a majority of students at this school write their names on their graphing calculators.
B
The teacher can be 99% confident that the interval from 46.5% to 81.5% captures the true proportion of students who write their names on their graphing calculators.
C
In 99% of samples taken, between 46.5% and 81.5% of the sampled students would write their names on their graphing calculators.
D
There is a 1% probability that the proportion of all students who write their names on their graphing calculators is either below 0.465 or above 0.815.
44

A laundry detergent company wants to determine if a new formula of detergent, A, cleans better than the original formula, B. Researchers randomly assign 500 pieces of similarly soiled clothes to the two detergents, putting 250 pieces in each group. After washing the clothes, independent reviewers determine the cleanliness of the clothes on a scale of 1–10, with 10 being the cleanest. The researchers calculate the proportion of clothes in each group that receive a rating of 7 or higher. For detergent A, 228 pieces of clothing received a 7 or higher. For detergent B, 210 pieces of clothing received a rating of 7 or higher. Assuming the conditions for inference are met, what is the 90% confidence interval for the difference in proportions of clothes that receive a rating of 7 or higher for the two detergents?Find the z-table here.

A
(0.91 minus 0.84) plus-or-minus 1.96 StartRoot StartFraction 0.91 (1 minus 0.91) Over 250 EndFraction + StartFraction 0.84 (1 minus 0.84) Over 250 EndFraction EndRoot
Option A
B
(0.91 minus 0.84) plus-or-minus 1.65 StartRoot StartFraction 0.91 (1 minus 0.91) Over 250 EndFraction + StartFraction 0.84 (1 minus 0.84) Over 250 EndFraction EndRoot
Option B
C
(0.09 minus 0.16) plus-or-minus 1.96 StartRoot StartFraction 0.09 (1 minus 0.09) Over 250 EndFraction + StartFraction 0.16 (1 minus 0.16) Over 250 EndFraction EndRoot
Option C
D
(0.09 minus 0.16) plus-or-minus 1.65 StartRoot StartFraction 0.09 (1 minus 0.09) Over 500 EndFraction + StartFraction 0.16 (1 minus 0.16) Over 500 EndFraction EndRoot
Option D
48

A computer company wants to determine if there is a difference in the proportion of defective computer chips in a day’s production from two different production plants, A and B. A quality control specialist takes a random sample of 100 chips from the first hour of production from plant A and determines that there are 12 defective chips. The specialist then takes a random sample of 100 chips from the last hour of production from plant B and determines that there are 10 defective chips. Assuming conditions for inference are met, what is the 90% confidence interval for the true difference in proportions of defective chips from a day’s production between the two plants? Find the z-table here.

A
(0.12 minus 0.10) plus-or-minus 1.96 StartRoot StartFraction 0.12 (1 minus 0.12) Over 100 EndFraction + StartFraction 0.10 (1 minus 0.10) Over 100 EndFraction EndRoot
Option A
B
(0.12 minus 0.10) plus-or-minus 1.65 StartRoot StartFraction 0.12 (1 minus 0.12) Over 100 EndFraction + StartFraction 0.10 (1 minus 0.10) Over 100 EndFraction EndRoot
Option B
C
(0.88 minus 0.90) plus-or-minus 1.96 StartRoot StartFraction 0.88 (1 minus 0.88) Over 100 EndFraction + StartFraction 0.90 (1 minus 0.90) Over 100 EndFraction EndRoot
Option C
D
(0.88 minus 0.90) plus-or-minus 1.65 StartRoot StartFraction 0.88 (1 minus 0.88) Over 100 EndFraction + StartFraction 0.90 (1 minus 0.90) Over 100 EndFraction EndRoot
Option D
49

A clinic measured the systolic blood pressure for a random sample of 10 patients. The resulting 95% confidence interval for the mean systolic blood pressure of all the patients at this clinic was (111.3, 129.5). A doctor commented that, on average, the patients at this clinic have high blood pressure, which is defined as blood pressure over 130. Based on the confidence interval, is the doctor’s statement justified?

A
Yes, because 130 is greater than the upper bound of the confidence interval.
B
Yes, because there were almost certainly some patients in the sample of 10 whose blood pressure was over 130.
C
No, because 130 is greater than the upper bound of the confidence interval.
D
No, because the sample mean blood pressure from the 10 sampled patients was 120.4.

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