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Precalculus
Solving Trigonometric Equations — Cumulative exam
Question 13
13
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Solving Trigonometric Equations — Cumulative exam
Question 13 • Precalculus
What is 4cos2(165°) – 2 expressed as a single trigonometric function?
Answer
A
4cos(330°)
B
2cos(330°)
C
4cos(82.5°)
D
2cos(82.5°)
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