AnswersDSD-CR-Secondary Math III-Term 3Cumulative Exam

Cumulative Exam — Cumulative exam Answers

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Law of sines:

Question illustration
A
4.6 units
B
5.7 units
C
6.9 units
D
9.2 units
42
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Which values of x satisfy the inequality

Question illustration
A
x greater-than-or-equal-to 5
Option A
B
x less-than-or-equal-to 5
Option B
C
x less-than-or-equal-to 8
Option C
D
x greater-than-or-equal-to 8
Option D
43

Law of sines:

Question illustration
A
52°
B
59°
C
64°
D
67°
44

If and are inverse functions of each other and , what is ?

Question illustration
A
mc005-5.jpg
Option A
B
mc005-6.jpg
Option B
C
mc005-7.jpg
Option C
D
mc005-8.jpg
Option D
45

Which of the following best explains why ?

Question illustration
A
The angles do not have the same reference angle.
B
Tangent is positive in the second quadrant and negative in the fourth quadrant.
C
Tangent is negative in the second quadrant and positive in the fourth quadrant.
D
The angles do not have the same reference angle or the same sign.
46

Trigonometric area formula: Area =

Question illustration
A
10.3 square units
B
18.0 square units
C
20.0 square units
D
20.6 square units
47

Law of cosines: a2 = b2 + c2 – 2bccos(A)

Question illustration
A
19°
B
26°
C
30°
D
33°
48

The area of parallelogram WXYZ is approximately 45 square units.Trigonometric area formula: Area =

Question illustration
A
5 units
B
15 units
C
30 units
D
40 units
49

On which triangle can the law of cosines be applied once to find an unknown angle measure?Law of cosines: a2 = b2 + c2 – 2bccos(A)

A
Triangle X W Y is shown. Angle X Y W is a right angle. The length of hypotenuse W X is y, the length of X Y is a, and the length of W Y is 9.
Option A
B
Triangle W X Y is shown. Sides W X and X Y are congruent. The length of W Y is 7.
Option B
C
Triangle W X Y is shown. Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.
Option C
D
Triangle W X Y is shown. The length of W X is 10, the length of X Y is 8, and the length of W Y is 16.
Option D
50

Law of cosines: a2 = b2 + c2 – 2bccos(A)

Question illustration
A
70°
B
77°
C
80°
D
85°

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