Cumulative Exam — Cumulative exam Answers

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1
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Which expression is equivalent to ?

Question illustration
A
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Option A
B
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Option B
C
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Option C
D
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Option D
2
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Which expression is equivalent to the expression below?

Question illustration
A
StartFraction 3 c (2 c minus 1) Over 2 c + 1 EndFraction
Option A
B
StartFraction negative 3 c (2 c + 1) squared Over 4 (2 c minus 1) squared EndFraction
Option B
C
3c
D
–3c
3

What are the values of x in the equation x2 – 6x + 9 = 25?

A
x = –2 or x = 8
B
x = –1 or x = –11
C
x = 1 or x = 11
D
x = 2 or x = –8
9

When graphed, which parabola opens downward?

Question illustration
y
y = –3x2
y
y = (x – 3)2
C
Option
Option C
y
y = x2 – 3
10

What is the quotient?

Question illustration
A
StartFraction 1 Over 2 y EnDfraction
Option A
B
StartFraction 3 y + 2 Over 6 y squared EndFraction
Option B
C
StartFraction 1 Over y EndFraction
Option C
D
StartFraction 2 (3 y + 2) Over 3 EndFraction
Option D
13

Which expression is equivalent to the following complex fraction?

Question illustration
A
StartFraction y + x Over y minus x EndFraction
Option A
B
StartFraction (y minus x) (y + x) Over x squared y squared EndFraction
Option B
C
StartFraction x squared y squared Over (y + x) (y + x) EndFraction
Option C
D
StartFraction y minus x Over y + x EndFraction
Option D
14

Solve for in the equation .

Question illustration
A
x = negative 11 plus-or-minus StartFraction 25 Over 2 EndFraction
Option A
B
x = negative eleven-halves plus-or-minus StartFraction 25 Over 2 EndFraction
Option B
C
x = negative 11 plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option C
D
x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Option D
16

If , which inequality can be used to find the domain of f(x)?

Question illustration
A
StartRoot 4 x EndRoot greater-than-or-equal-to 0
Option A
B
4 x + 9 greater-than-or-equal-to 0
Option B
C
4 x greater-than-or-equal-to 0
Option C
D
StartRoot 4 x + 9 EndRoot + 2 greater-than-or-equal-to 0
Option D
17

What is the product?

Question illustration
A
StartFraction k + 1 Over k squared EndFraction
Option A
B
StartFraction k minus 1 Over k squared EndFraction
Option B
C
StartFraction negative 1 Over k EndFraction
Option C
D
StartFraction 1 Over k EndFraction
Option D
19

Tyna simplified the expression to . What was Tyna’s mistake?

Question illustration
S
She divided the coefficients incorrectly.
S
She added the exponents instead of subtracting them.
S
She divided the coefficients instead of subtracting them.
S
She subtracted the exponents instead of dividing them.

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