Unit Test — Cumulative exam Answers

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How is the graph of transformed to produce the graph of ?

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T
The graph is stretched horizontally by a factor of 2 and then moved right 4 units.
T
The graph is compressed horizontally by a factor of 2 and then moved down 4 units.
T
The graph is compressed horizontally by a factor of 2, moved left 4 units, and moved down 4 units.
T
The graph is stretched horizontally by a factor of 2, moved left 4 units, and moved down 4 units.
3

What is the solution of ?

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A
x = –17
B
x = 13
C
x = 53
D
no solution
5

If you are given the graph of , how could you graph ?

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T
Translate each point of the graph of g(x) 5 units up.
T
Translate each point of the graph of g(x) 5 units down.
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Translate each point of the graph of g(x) 5 units left.
T
Translate each point of the graph of g(x) 5 units right.
8

Which graph represents the function ?

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A
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 3, and the horizontal asymptote is at y = negative 2.
Option A
B
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens down and to the left in quadrants 2 and 3. A vertical asymptote is at x = 3, and the horizontal asymptote is at y = negative 2.
Option B
C
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens down and to the left in quadrants 2 and 3. A vertical asymptote is at x = negative 3, and the horizontal asymptote is at y = 2.
Option C
D
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1 , and the other curve opens down and to the left in quadrants 2, 1, and 4. A vertical asymptote is at x = 3, and the horizontal asymptote is at y = 2.
Option D
9

Riley makes a mistake in step 2 while doing her homework. What was her mistake? Step 1: Step 2: Step 3: Step 4:

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A
She added the two fractions incorrectly.
B
She used the wrong common denominator.
C
She did not distribute the negative correctly.
D
She did not multiply the first fraction by a factor.
14

What is rewritten using the power property?

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A
e log Subscript 6 Baseline f
Option A
B
f log Subscript 6 Baseline e
Option B
C
log Subscript 6 Baseline (e times f)
Option C
D
log Subscript 6 Baseline (e + f)
Option D
16

Which function has the same maximum value as f(x) = – |x + 3| – 2?

A
Option
Option A
B
f(x) = (x + 3)2 – 2
C
Option
Option C
D
f(x) = –(x – 6)2 – 3
18

What is the range of ?

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a
all real numbers not equal to 0
a
all real numbers less than 6
a
all real number greater than 6
a
all real numbers
20

Which expression is equivalent to ?

Question illustration
A
Negative 4 x Superscript 4 Baseline y Superscript 6
Option A
B
Negative 8 x Superscript 4 Baseline y Superscript 6
Option B
C
StartFraction 4 x Superscript 4 Baseline Over y Superscript 6 EndFraction
Option C
D
StartFraction 8 x Superscript 4 Baseline Over y Superscript 6 Baseline EndFraction
Option D

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