Unit Test — Cumulative exam Answers

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Based upon historical data, it is known that 8% of 12-egg cartons contain at least one broken egg. A grocery store manager would like to carry out a simulation to estimate the number of cartons, in a sample of 10, that would contain at least one broken egg. What is an appropriate assignment of digits for this simulation?

A
Let 01-08 = the carton contains a broken egg. Let 09-99 and 00 = the carton does not contain a broken egg.
B
Let 09-99 and 00 = the carton contains a broken egg. Let 01-08 = the carton does not contain a broken egg.
C
Let 1-8 = the carton contains a broken egg. Let 9 and 0 = the carton does not contain a broken egg.
D
Let 9 and 0 = the carton contains a broken egg. Let 1-8 = the carton does not contain a broken egg.
3

The ages of the 5 officers for a school club are 18, 18, 17, 16, and 15. The minimum of the ages of the officers is 15. The table displays all possible samples of size 2 and the corresponding minimum for each sample.Using the minimums in the table, is the sample minimum an unbiased estimator?

Question illustration
A
Yes, 15 occurred the most in the sample minimums.
B
Yes, the minimum of the sampling distribution of the minimums is 15.
C
No, 60% of the possible minimum values of the samples is more than 15.
D
No, the mean of the sampling distribution of the sample minimums is 16, which is not 15.
5

A therapist wanted to determine if yoga or meditation is better for relieving stress. The therapist recruited 100 of her high-stress patients. Fifty of them were randomly assigned to take weekly yoga classes, and the other 50 were assigned weekly meditation classes. After one month, 30 of the 50 patients in the yoga group reported less stress, and 35 of the 50 patients in the meditation group reported less stress. Assuming the conditions for inference are met, what is the 95% confidence interval for the difference in proportions of patients experiencing stress relief from the yoga and meditation groups?Find the z-table here.

A
(0.40 minus 0.30) plus-or-minus 1.65 StartRoot StartFraction 0.40 (1 minus 0.40) Over 100 EndFraction + StartFraction 0.30 (1 minus 0.30) Over 100 EndFraction EndRoot
Option A
B
(0.60 minus 0.70) plus-or-minus 1.96 StartRoot StartFraction 0.60 (1 minus 0.60) Over 100 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 100 EndFraction EndRoot
Option B
C
(0.60 minus 0.70) plus-or-minus 1.65 StartRoot StartFraction 0.60 (1 minus 0.60) Over 50 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 50 EndFraction EndRoot
Option C
D
(0.60 minus 0.70) plus-or-minus 1.96 StartRoot StartFraction 0.60 (1 minus 0.60) Over 50 EndFraction + StartFraction 0.70 (1 minus 0.70) Over 50 EndFraction EndRoot
Option D
6

A teacher would like to estimate the mean amount of time it takes for students taking this statistics class to complete this multiple-choice assessment item. To do so, she selects a random sample of 50 students enrolled in this statistics class and records the amount of time (in minutes) it takes them to complete this question. The standard error of the mean is 0.27 minutes. What is the interpretation of the standard error of the mean?

A
In the random sample of 50 students, the mean amount of time needed to complete this question is about 0.27 minutes.
B
If we select many random samples of students enrolled in this statistics class, the mean amount of time needed to complete this question is about 0.27 minutes.
C
In the random sample of 50 students, the sample mean amount of time needed to complete this question varied by about 0.27 minutes from the population mean.
D
If we select many random samples of students enrolled in this statistics class, the sample mean amount of time needed to complete this question would typically vary by about 0.27 minutes from the population mean.
8

Animal shelters in a county need at least 15% of their animals to be adopted weekly to have room for the new animals that are brought into the various shelters. The county manager takes a random sample of shelters each week to estimate the overall proportion of animals that are adopted. If he concludes that the proportion has dropped below 15%, he will not accept any new animals into the shelters that week. He tests the hypotheses: H0: The adoption rate is 15%, and Ha: The adoption rate is less than 15%. What is a Type I error, and what is its consequence in this context?

A
The manager believes the adoption rate is still 15%, when it actually has dropped below 15%. The manager will accept more animals into the shelters and will run out of room.
B
The manager believes the adoption rate has dropped below 15%, when it actually has not. The manager will accept more animals into the shelters and will run out of room.
C
The manager believes the adoption rate has dropped below 15%, when it actually has not. The manager will not accept more animals into the shelters, when there actually is room to care for those animals.
D
The manager believes the adoption rate is still 15%, when it actually has dropped below 15%. The manager will not accept some animals into the shelters, thinking there will not be enough room, when they could have taken care of those animals.
12

A doctor would like to estimate the mean difference in height of pairs of identical twins. The doctor randomly selects 8 pairs of identical twins and determines the current height, in inches, of each twin. The data are displayed in the table.The conditions for inference are met. The 95% confidence interval for the mean difference (twin 1 – twin 2) in height is (–0.823, 0.573). What is the correct interpretation of this interval?

Question illustration
A
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean height of twins.
B
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean height of twins in this sample.
C
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean difference in the height of twins.
D
The doctor can be 95% confident that the interval from –0.823 inches to 0.573 inches captures the true mean difference in the height of the twins in this sample.
13

A racecar driver has a 0.05 probability of winning any given race in a season. There are 16 races in a season, and whether or not the driver wins one race is independent of whether he wins any other race. Let X represent the number of races the driver wins in the season.Have the conditions for a binomial setting been met for this scenario?

A
No, a sample size of 16 races is too small.
B
Yes, all four conditions in BINS have been met.
C
No, the probability of winning is too small for a binomial setting.
D
Yes, but they will only have been met if the racecar driver improves the probability of winning a race as the season progresses.
14

The mean weight for a typical bunch of bananas in grocery stores is 3.54 pounds. The owner of a grocery store will reject a shipment of bananas if the mean weight of the banana bunches is less than 3.54 pounds. The owner randomly selects and weighs 30 bunches of bananas. A significance test at an alpha level of tests the hypotheses pounds; pounds. What is a Type II error in this situation?

Question illustration
A
Based on the sample mean, the owner concludes that the mean weight of all of the bunches of bananas is less than 3.54 pounds when the true mean weight is less than 3.54 pounds.
B
Based on the sample mean, the owner concludes that the mean weight of all of the bunches of bananas is not less than 3.54 pounds when the true mean weight is not less than 3.54 pounds.
C
Based on the sample mean, the owner concludes that the mean weight of all of the bunches of bananas is less than 3.54 pounds when the true mean weight is actually not less than 3.54 pounds.
D
Based on the sample mean, the owner concludes that the mean weight of all of the bunches of bananas is not less than 3.54 pounds when the true mean weight is actually less than 3.54 pounds.
15

Can you train yourself to become better at holding your breath? An experiment was designed to find out. A group of 12 volunteers were randomly assigned to 1 of 2 groups. The 6 volunteers assigned to group 1 were given breath-holding exercises to perform for 2 weeks. The other group was not given any information about the experiment. At the end of the 2 weeks, all 12 volunteers were individually tested to determine how long they could hold their breath. Here are the data (in seconds):Group 1: 90, 88, 70, 110, 75, 105Group 2: 40, 48, 35, 50, 55, 62

A
Reject H0. There is convincing evidence that the volunteers who were given training held their breath longer, on average, than the volunteers without training.
B
Reject H0. There is convincing evidence that the true mean amount of time volunteers who were given training held their breath is greater than the true mean amount of time volunteers without training held their breath.
C
Fail to reject H0. There is not convincing evidence that the volunteers who were given training held their breath longer, on average, than the volunteers without training.
D
Fail to reject H0. There is not convincing evidence that the true mean amount of time volunteers who were given training held their breath is greater than the true mean amount of time volunteers without training.
18

Consider the given probability histogram of a binomial random variable.

Question illustration
A
Center: 2Shape: skewed left
B
Center: 2.4Shape: skewed right
C
Center: 2.4Shape: skewed left
D
Center: 3.Shape: skewed right
19

The prices of houses in the US is strongly skewed to the right with a mean of $383,500 and a standard deviation of $289,321. A real estate agent takes a random sample of 30 houses and records the mean price. What is the best description for the sampling distribution?

A
skewed to the right with a mean of 383,500 and a standard deviation of 52,823
B
skewed to the right with a mean of 383,500 and a standard deviation of 289,321
C
approximately Normal with a mean of 383,500 and a standard deviation of 52,823
D
approximately Normal with a mean of 383,500 and a standard deviation of 289,321

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