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CR03101 Chemistry
Cumulative Exam
Question 43
43
Quiz
Multiple Choice
Cumulative Exam
Question 43 of 50 • CR03101 Chemistry
Consider the reaction below.2C6H14 + 19O2 12CO2 + 14H2OHow many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?
Answer
A
1.53 mol
B
3.07 mol
C
110. mol
D
175. mol
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Cumulative Exam - Question 43 | CR03101 Chemistry | Revolt