Question 24 • 26-27 Ignite Technical Math-Financial Math - MA2007
Let N be newspaper ads and T be television ads. The requirement is N/T ≥ 5/3, and the total must be no more than 62. Choice C has 40 newspaper ads and 21 television ads: 40/21 is greater than 5/3, and 40 + 21 = 61. The other choices either exceed the 62-ad limit or fail the required ratio, so C allows the greatest total while meeting both conditions.
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