Dividing Radicals Answers

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1
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To rationalize the denominator of , you should multiply the expression by which fraction?

Question illustration
A
StartFraction 5 + StartRoot 7 EndRoot Over 9 minus StartRoot 14 EndRoot EndFraction
Option A
B
StartFraction 9 minus StartRoot 14 EndRoot Over 9 minus StartRoot 14 EndRoot EndFraction
Option B
C
StartFraction 9 + StartRoot 14 EndRoot Over 9 + StartRoot 14 EndRoot EndFraction
Option C
D
StartFraction StartRoot 14 EndRoot Over StartRoot 14 EndRoot EndFraction
Option D
2
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What is the following quotient?

Question illustration
A
2 StartRoot 3 EndRoot
Option A
B
4
C
2 StartRoot 22 EndRoot
Option C
D
12
3

The radius of a circle with an area of 60 square centimeters is represented by the expression centimeters. What is another way of expressing the radius?

Question illustration
A
2 StartRoot 15 pi EndRoot
Option A
B
4 StartRoot 5 pi EndRoot
Option B
C
StartFraction 2 StartRoot 15 pi EndRoot Over pi EndFraction
Option C
D
StartFraction 4 StartRoot 5 pi EndRoot Over pi EndFraction
Option D
4

What is the simplified form of the following expression? Assume .

Question illustration
A
StartFraction 2 (RootIndex 3 StartRoot 6 x squared y squared EndRoot) Over y EndFraction
Option A
B
StartFraction RootIndex 3 StartRoot 12 x squared y EndRoot Over 2 y EndFraction
Option B
C
StartFraction x (RootIndex 3 StartRoot 3 y EndRoot) Over 2 y EndFraction
Option C
D
StartFraction RootIndex 3 StartRoot 6 x squared y squared EndRoot Over 2 y EndFraction
Option D
5

What is the following quotient?

Question illustration
A
StartFraction 12 StartRoot 2 EndRoot minus 6 StartRoot 3 EndRoot Over 5 EndFraction
Option A
B
StartFraction 3 StartRoot 6 EndRoot minus 4 StartRoot 3 EndRoot Over 24 EndFraction
Option B
C
StartFraction StartRoot 3 EndRoot Over 12 EndFraction
Option C
D
StartFraction StartRoot 3 EndRoot Over 2 EndFraction
Option D
7

What is the following quotient?

Question illustration
A
StartFraction 12 StartRoot 2 EndRoot minus 6 StartRoot 3 EndRoot Over 5 EndFraction
Option A
B
StartFraction 3 StartRoot 6 EndRoot minus 4 StartRoot 3 EndRoot Over 24 EndFraction
Option B
C
StartFraction StartRoot 3 EndRoot Over 12 EndFraction
Option C
D
StartFraction StartRoot 3 EndRoot Over 2 EndFraction
Option D
8

What is the simplified form of the following expression? Assume .

Question illustration
A
StartFraction 2 (RootIndex 3 StartRoot 6 x squared y squared EndRoot) Over y EndFraction
Option A
B
StartFraction RootIndex 3 StartRoot 12 x squared y EndRoot Over 2 y EndFraction
Option B
C
StartFraction x (RootIndex 3 StartRoot 3 y EndRoot) Over 2 y EndFraction
Option C
D
StartFraction RootIndex 3 StartRoot 6 x squared y squared EndRoot Over 2 y EndFraction
Option D
9

Which expression is equivalent to ?

Question illustration
A
One-fourth
Option A
B
RootIndex 6 StartRoot 2 EndRoot
Option B
C
StartRoot 2 EndRoot
Option C
D
StartFraction StartRoot 2 EndRoot Over 2 EndFraction
Option D
10

What is the following quotient?

Question illustration
A
StartFraction StartRoot 3 EndRoot minus StartRoot 6 EndRoot Over 4 EndFraction
Option A
B
StartFraction 2 + StartRoot 3 EndRoot minus 2 StartRoot 2 EndRoot minus StartRoot 6 EndRoot Over 4 EndFraction
Option B
C
2 minus StartRoot 3 EndRoot minus 2 StartRoot 2 EndRoot + StartRoot 6 EndRoot
Option C
D
StartFraction negative 2 minus StartRoot 3 EndRoot + 2 StartRoot 2 EndRoot + StartRoot 6 EndRoot Over 2 EndFraction
Option D

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