A sample of iron Fe with a mass of 200.0g releases 9 comma 840 cal when it freezes at its freezing point. What is the molar heat of fusion for iron? Use q is equal to n triangle cap h

First find the amount of iron: 200.0 g ÷ 55.85 g/mol ≈ 3.581 mol. The sample releases 9,840 cal as it freezes, so the heat of fusion is the same amount per mole in magnitude: 9,840 cal ÷ 3.581 mol ≈ 2,747.7 cal/mol. The molar heat of fusion is therefore 2,747.7 cal/mol, choice B.

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