Nitrogen dioxide, NO sub 2 times g ΔH_f=33.84kJ/mol , is decomposed according to the reaction: 2 NO sub 2 g rightarrow cap n sub 2 times g plus 2 cap o sub 2 g What is the enthalpy change when 2 point 5 0 mol of nitrogen dioxide decomposes? Use ΔH_rxn=∑(ΔH_f_1products)−∑(ΔH_f_1reactants)
Answer
A
13 point 5 kJ of energy absorbed
B
13 point 5 kJ of energy released
C
84 point 6 kJ of energy released
D
84 point 6 kJ of energy absorbed
Explanation
The elements N₂(g) and O₂(g) have standard enthalpies of formation of 0. For the reaction as written, ΔH_rxn = 0 − 2(33.84 kJ/mol) = −67.68 kJ per 2 mol of NO₂. For 2.50 mol, the change is (2.50 ÷ 2)(−67.68 kJ) = −84.6 kJ. The negative sign means 84.6 kJ of energy is released, so the answer is choice C.
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