AnswersGeometry - Semester 1 PathwaysTriangle Similarity: SSS and SAS (Sec 7-3, 7-4, 7-5)

Exploring the Pythagorean Theorem Answers

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Consider the two triangles.

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A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
2
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Consider △RST and △RYX.

Question illustration
A
StartFraction R Y Over Y S EndFraction = StartFraction R X Over X T EndFraction = StartFraction X Y Over T S EndFraction
Option A
B
StartFraction R Y Over R S EndFraction = StartFraction R X Over R T EndFraction = StartFraction X Y Over T S EndFraction
Option B
C
StartFraction R Y Over R S EndFraction = StartFraction R X Over R T EndFraction = StartFraction R S Over R Y EndFraction
Option C
D
StartFraction R Y Over R X EndFraction = StartFraction R S Over R T EndFraction = StartFraction X Y Over T S EndFraction
Option D
3

Read the proof.Given: AB ∥ DEProve: △ACB ~ △DCE

Question illustration
A
AA similarity theorem.
B
SSS similarity theorem.
C
AAS similarity theorem.
D
ASA similarity theorem.
4

Which best explains why all equilateral triangles are similar?

A
All equilateral triangles can be mapped onto each other using dilations.
B
All equilateral triangles can be mapped onto each other using rigid transformations.
C
All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
D
All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
6

Triangle ABC was dilated using the rule .

Question illustration
A
10 units
B
12 units
C
16 units
D
20 units
7

Triangles R S T and V U T are connected at point T. Angles R S T and V U T are right angles. The length of side R S is 12 and the length of side S T is 16. The length of side T U is 8 and the length of U V is 6.

Question illustration
A
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U
Option A
B
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction = StartFraction R T Over V T EndFraction
Option B
C
StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction and angle S is-congruent-to angle U
Option C
D
StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction = StartFraction R T Over V T EndFraction
Option D
8

In the diagram, DG = 12, GF = 4, EH = 9, and HF = 3.

Question illustration
A
∠DFE is 4 times greater than ∠GFH.
B
∠FHG is the measure of ∠FED.
Option B
C
∠DFE is congruent to ∠GFH.
D
∠FHG is congruent to ∠EFD.
9

Point P is the center of dilation. Triangle A B C is dilated to create triangle A prime B prime C prime. The length of P A is 2 and the length of P B is 3. The Length of A A prime is 4 and the length of B B prime is 5.

Question illustration
A
Yes, it is an enlargement with a scale factor of 3.
B
Yes, it is an enlargement with a scale factor of .
Option B
C
No, it is not a dilation because the points of the image are not moved away from the center of dilation proportionally.
D
No, it is not a dilation because the sides of the image are proportionally reduced from the pre-image.
11

Triangles L M N and P O N connect at point N. Angles L M N and N O P are congruent.

Question illustration
A
because both triangles appear to be equilateral
B
because∠MNL and ∠ONP are congruent angles
C
because one pair of congruent corresponding angles is sufficient to determine similar triangles
D
because both triangles appear to be isosceles, ∠MLN ≅ ∠LMN, and ∠NOP ≅ ∠OPN
13

In the diagram, .

Question illustration
A
MN and SR
B
MN and QR
C
∠S ≅ ∠N
D
∠S ≅ ∠O
14

The composition is applied to △RST to create the image of △R"S"T", which is not shown.

Question illustration
A
(negative three-halves, nine-halves)
Option A
B
(negative nine-halves, fifteen-halves)
Option B
C
(nine-halves, negative three-halves)
Option C
D
(negative fifteen-halves, 0)
Option D
15

Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C.

Question illustration
A
∠BDC and ∠AED are right angles
B
AE ≅ ED
C
△BDC is a right triangle
D
∠DBC ≅ ∠DCB
18

Which would prove that ΔABC ~ ΔXYZ? Select two options.

A
StartFraction B A Over Y X = StartFraction B C Over Y Z EndFraction = StartFraction A C Over X Z EndFraction
Option A
B
StartFraction B A Over Y X = StartFraction B C Over Y Z EndFraction , angle C is-congruent-to angle Z
Option B
C
StartFraction A C Over X Z EndFraction = StartFraction B A Over Y X EndFraction , Angle A is-congruent-to Angle X
Option C
D
StartFraction B A Over Y X EndFraction = StartFraction A C Over Y Z EndFraction = StartFraction B C Over X Z EndFraction
Option D
E
StartFraction B C Over X Y EndFraction = StartFraction B A Over Z X EndFraction , Angle C is-congruent-to angle X.
Option E
19

△RST ~ △RYX by the SSS similarity theorem.

Question illustration
A
StartFraction X Y Over T S EndFraction
Option A
B
StartFraction S Y Over R Y EndFraction
Option B
C
StartFraction R X Over X T EndFraction
Option C
D
StartFraction S T Over Y X EndFraction
Option D

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