Answers NY-Algebra I Term 2 Hillcrest Factoring Polynomials CompletelyQuestion 5

5

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Factoring Polynomials Completely

Question 5 • NY-Algebra I Term 2 Hillcrest

Antonia is factoring the polynomial, which has four terms.21x3−63x2+15x−453[7x3−21x2+5x−15]3[7x2(x−3)+5(x−3)]

Answer

2

21x2(x − 3)

3

36x2(x − 3)

3

3(7x2 + 5) (x − 3)

3

3(12x2 + 5) (x − 3)

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