AnswersCrowley Summer 26 Credit Recovery Algebra 2 ASolving Systems of Equations in Three Variables

Factoring Polynomials: Sum and Difference of Cubes Answers

10 verified answers
1
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What is the factorization of 216x12 – 64?

A
(6x3 – 4)(36x6 + 24x3 + 16)
B
(6x3 – 4)(36x9 + 24x3 + 16)
C
(6x4 – 4)(36x8 + 24x4 + 16)
D
(6x4 – 4)(36x12 + 24x4 + 16)
3

Which is a difference of cubes?

x
x6 – 27
x
x15 – 36
x
x16 – 64
x
x5 – 125
4

Which monomial is a perfect cube?

A
49p9q3r24
B
81p12q15r12
C
121p9q3r6
D
343p6q21r6
5

What is the factorization of 729x15 + 1000?

A
(9x5 + 10)(81x10 – 90x5 + 100)
B
(9x5 + 10)(81x5 – 90x10 + 100)
C
(9x3 + 10)(81x6 – 90x6 + 100)
D
(9x3 + 10)(81x9 – 90x3 + 100)
6

Which product will result in a sum or difference of cubes?

(
(x + 7)(x2 – 7x + 14)
(
(x + 8)(x2 + 8x + 64)
(
(x – 9)(x2 + 9x + 81)
(
(x – 10)(x2 – 10x + 100)
8

Which statements are true about a perfect cube monomial and its roots? Check all that apply.A perfect cube monomial must have exponents on the variables.A perfect cube monomial must have three identical roots, such that the product of the roots equal the perfect square monomial.The coefficient of the monomial must be divisible by 3.Any monomial can be a perfect cube root.The least common multiple of all the exponents on variables of a perfect cube monomial must be 3.It must be possible for the coefficient of a perfect cube monomial to be written in the form n3, where n equals the cube root of the coefficient.

A
A perfect cube monomial must have exponents on the variables.
B
A perfect cube monomial must have three identical roots, such that the product of the roots equal the perfect square monomial.
C
The coefficient of the monomial must be divisible by 3.
D
Any monomial can be a perfect cube root.
E
The least common multiple of all the exponents on variables of a perfect cube monomial must be 3.
F
It must be possible for the coefficient of a perfect cube monomial to be written in the form n3, where n equals the cube root of the coefficient.
9

What is 125x9 + 64y12 written as a sum of cubes?

(
(25x3)3 + (4y4)3
(
(5x3)3 + (16y4)3
(
(25x3)3 + (8y4)3
(
(5x3)3 + (4y4)3

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