r(x) = –x² + 3x s(x) = 2x + 1(s – r)(x) = –x² + 3x – 2x + 1(–x² + 3x) – (2x + 1)✔ (2x + 1) – (–x² + 3x)2x + 1 – x² + 3x

To find (s − r)(x), subtract r(x) from s(x): (2x + 1) − (−x² + 3x). This matches choice C. Distributing the subtraction gives x² − x + 1.

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