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KISD SS-3391B-Algebra II Honors B
Graphs of Rational Functions
Question 6
6
Quiz
Multiple Choice
Graphs of Rational Functions
Question 6 of 9 • KISD SS-3391B-Algebra II Honors B
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Answer
A
f(x) has one real zero at –2 because the graph of the function has an intercept at (0, –2).
B
f(x) has two real zeros at –4 and –2 because the graph of the function has intercepts at (–4, 0) and (0, –2).
C
f(x) has no real zeros because the graph of the function does not pass through (0, 0).
D
f(x) has one real zero at –4 because the graph of the function has an intercept at (–4, 0).
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