A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form?

First multiply A and B: n(2n + 6) = 2n² + 6n. Then subtract C, remembering to subtract the entire expression n² − 1: (2n² + 6n) − (n² − 1) = n² + 6n + 1. This matches choice B, n² + 6n + 1.

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